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In the circuit shown in the figure, the input voltage Vi is 20 V, VBE = 0 and VCE = 0. The values of IB, IC and β are given by

1. IB = 40 μA, IC = 10 mA, β = 250
2. IB = 25 μA, IC = 5 mA, β = 200
3. IB = 40 μA, IC = 5 mA, β = 125
4. IB = 20 μA, IC = 5 mA, β = 250

Correct answer: IB = 40 μA, IC = 5 mA, β = 125

Solution

Using the relationship IC = β * IB and the given values, IB = 40 μA and IC = 5 mA satisfy β = 125. This matches the circuit conditions provided.

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