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In a common emitter (CE) amplifier having a voltage gain G, the transistor used has transconductance 0.03 mho and current gain 25. If the above transistor is replaced with another one with transconductance 0.02 mho and current gain 20, the voltage gain will be:

1. 1.5 G
2. 1/3 G
3. 5/4 G
4. 2/3 G

Correct answer: 2/3 G

Solution

The voltage gain (G) in a CE amplifier is proportional to the product of the transconductance (gm) and the load resistance (RL). Since RL remains constant, the ratio of the new voltage gain to the old voltage gain is equal to the ratio of the new gm to the old gm. The ratio is (0.02 × 20) / (0.03 × 25) = 2/3. Thus, the new voltage gain is 2/3 G.

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