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An npn transistor is connected in common emitter configuration in a given amplifier. A load resistance of 800 Ω is connected in the collector circuit and the voltage drop across it is 0.8 V. If the current amplification factor is 0.96 and the input resistance of the circuit is 192 Ω, the voltage gain and the power gain of the amplifier will respectively be:

1. 4, 3.84
2. 3.69, 3.84
3. 4, 4
4. 4, 3.69

Correct answer: 4, 3.84

Solution

The voltage gain is given by Av = β × (RL / Rin), where β is the current amplification factor, RL is the load resistance, and Rin is the input resistance. Substituting the values, Av = 0.96 × (800 / 192) = 4. The power gain is approximately Av × β = 4 × 0.96 = 3.84.

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