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Concentrated HNO3 reacts with NaCN and Na2S to eliminate their interference. Which of the following reactions correctly represents this process?
- NaCN reacts with HNO3 to produce NaNO3 and release HCN gas.
- Na2S reacts with 2 moles of HNO3 to form 2 moles of NaNO3 and release H2S gas.
- The stability of a carbanion increases with a higher percentage of 's' character.
- Electron-donating groups reduce the stability of a carbanion.
Correct answer: NaCN reacts with HNO3 to produce NaNO3 and release HCN gas.
Solution
Option A is correct because concentrated HNO3 reacts with NaCN to produce NaNO3 and HCN gas, which aligns with the decomposition reaction described.
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