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True statements for the chemical reaction of the formation of lithium oxide is: \( 4 L i(s)+O_{2}(g) \rightarrow 2 L i_{2} O(s) \)

1. lithium metal is the oxidizing agent
2. oxygen gas is the reducing agent
3. lithium is oxidized
4. oxygen is oxidized E. oxygen loses two electrons to become \( O^{-2} \) ion

Correct answer: lithium is oxidized

Solution

In Li2O, lithium is present as Li+ and oxygen as O2−. Since lithium goes from oxidation state 0 in Li(s) to +1 in the product, lithium is oxidized; oxygen is reduced.

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