Exams › NEET › Chemistry

Out of the following redox reactions \( \boldsymbol{I} \cdot \boldsymbol{N} \boldsymbol{H}_{4} \boldsymbol{N} \boldsymbol{O}_{3} \stackrel{\Delta}{\rightarrow} \boldsymbol{N}_{2} \boldsymbol{O}+\boldsymbol{2} \boldsymbol{H}_{2} \boldsymbol{O} \) III.N \( \boldsymbol{H}_{4} \boldsymbol{N} \boldsymbol{O}_{2} \stackrel{\Delta}{\rightarrow} \boldsymbol{N}_{2}+\mathbf{2} \boldsymbol{H}_{2} \boldsymbol{O} \) IIII.PCl\( _{5} \stackrel{\Delta}{\rightarrow} P C l_{3}+C l_{2} \) disproportionation is not shown in:

1. I and II
2. II and III
3. I and III
4. I, II and III

Correct answer: I and III

Solution

In reaction I, nitrogen goes from -3 in NH4NO3 to an average of +1 in N2O, but the redox change is not a disproportionation of a single oxidation state into two different ones. In reaction III, phosphorus in PCl5 is simply reduced from +5 to +3 while chlorine is oxidized from -1 to 0, so it is not disproportionation either.

Related NEET Chemistry questions

• True statements for the chemical reaction of the formation of lithium oxide is: \( 4 L i(s)+O_{2}(g) \rightarrow 2 L i_{2} O(s) \)
• ¡) \( \boldsymbol{H}_{2} \boldsymbol{O}_{2} \rightarrow \boldsymbol{H}_{2} \boldsymbol{O}+(\boldsymbol{o}) \) ii) \( \boldsymbol{H}_{2} \boldsymbol{O}_{2}+\boldsymbol{2} \boldsymbol{I}^{-} \rightarrow \boldsymbol{I}_{2}+\boldsymbol{2} \boldsymbol{O} \boldsymbol{H}^{-}, \boldsymbol{H}_{2} \boldsymbol{O}_{2} \) acts as:
• In the following redox reaction: \( \boldsymbol{Z} \boldsymbol{n}(\boldsymbol{s})+\boldsymbol{N} \boldsymbol{O}_{\boldsymbol{3}}^{-}(\boldsymbol{a} \boldsymbol{q})+\boldsymbol{H}^{+}(\boldsymbol{a} \boldsymbol{q}) \longrightarrow \) \( Z n^{2+}(a q)+N H_{4}^{+}(a q) \) \( Z n(s) \) and \( N O_{3}^{-}(a q) \) respectively are respectively:
• One mole of \( H N O_{3} \) absorbs 5 moles of electrons in a redox reaction. The reduced product of this reaction is :
• Given below is a redox reaction. Which of the following types the reaction belong to? \( \boldsymbol{C u}^{+\mathbf{2 + 6 - 2}} \boldsymbol{O}_{4(a q)}+\boldsymbol{Z} \boldsymbol{n}_{(s)} \rightarrow \boldsymbol{C u}_{(s)}+ \) \( \underset{Z n S O_{4(a q)}}{+2+6+-2} \)
• When the gases; sulphur dioxide and hydrogen sulphide mix in the presence of water, the reaction \( S O_{2}+2 H_{2} S \rightarrow \) \( 2 H_{2} O+3 S \) occurs Here hydrogen sulphide is acting as:

⚔️ Practice NEET Chemistry free + battle 1v1 →