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The formula for orbital angular momentum is expressed as h/2π √(l(l+1)). For a p orbital, where l equals 1, the angular momentum becomes h √2/2π.

1. h/2π √(l(l+1))
2. h √2/2π
3. h/2π √2
4. h √(l+1)/2π

Correct answer: h √2/2π

Solution

The formula for orbital angular momentum is L = h/2π √(l(l+1)). For a p orbital, l = 1. Substituting l = 1 into the formula gives L = h/2π √(1(1+1)) = h/2π √2 = h √2/2π, which matches option B.

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