Exams › NEET › Chemistry

From the \( \alpha \) -particle scattering experiment, Rutherford concluded that: This question has multiple correct options

1. \( \alpha \) -particles can approach within a distance of the order of \( 10^{-14} \mathrm{m} \) of the nucleus
2. the radius of the nucleus is less than \( 10^{-14} m \)
3. scattering follows Coulomb's law
4. the positively charged parts of the atom move with extremely high velocities

Correct answer: the radius of the nucleus is less than \( 10^{-14} m \)

Solution

Rutherford’s scattering showed that most of the atom is empty space and that the positive charge is concentrated in a tiny central nucleus. The existence of strong deflections at very small impact parameters implies the nucleus must have a radius smaller than about \(10^{-14}\,\text{m}\).

Related NEET Chemistry questions

• Protons and neutrons are also called
• Which of following was not explained by Rutherford?
• The energy of an electron in the ground state of \( \boldsymbol{H} \) atom is \( -\mathbf{1 3 . 6 e V} \) The negative sign indicates that:
• Outer electronic configuration of Cl⁻ is:
• The sub-shell with lowest value of (n + l) is filled up first. When two or more sub-shells have the same (n + l) value, the sub-shell with lowest value of 'n' is filled up first. Therefore, the correct order is:
• The number of d-electrons in Fe²⁺ (Z = 26) is not equal to the number of electrons in which one of the following?

⚔️ Practice NEET Chemistry free + battle 1v1 →