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In octahedral complexes with the formulas MA4B2 and MA2B4, geometrical isomerism is not exhibited.

1. MA4B2 - Two possible geometrical isomers
2. MA2B4 - Two possible geometrical isomers
3. MA4B2 - No geometrical isomers
4. MA2B4 - No geometrical isomers

Correct answer: MA4B2 - Two possible geometrical isomers

Solution

In an octahedral geometry, MA4B2 can exhibit geometrical isomerism as the two B ligands can be arranged either cis or trans to each other. However, MA2B4 does not show geometrical isomerism because the four B ligands dominate the geometry, leaving no distinct cis or trans arrangement for the A ligands.

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