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ExamsNEETChemistry

The IUPAC name of \( \left[\mathrm{Ni}\left(\mathrm{NH}_{3}\right)_{4}\right]\left[\mathrm{NiCl}_{4}\right] \) is :

  1. tetrachloronickel (II)-tetraaminenickel (II)
  2. tetramminenickel (II)-tetrachloronickel (II)
  3. tetraamminenickel (II)-tetrachloronickelate (II)
  4. tetrachloronickel (II)-tetraaminenickelate (0)

Correct answer: tetraamminenickel (II)-tetrachloronickelate (II)

Solution

In [Ni(NH3)4], NH3 is neutral, so Ni is +2 and the cation is tetraamminenickel(II). In [NiCl4], each Cl is -1, so Ni is +2 and because the complex is an anion, the metal name becomes nickelate: tetrachloronickelate(II).

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