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The IUPAC name of \( \left[\mathrm{Ni}\left(\mathrm{NH}_{3}\right)_{4}\right]\left[\mathrm{NiCl}_{4}\right] \) is :
- tetrachloronickel (II)-tetraaminenickel (II)
- tetramminenickel (II)-tetrachloronickel (II)
- tetraamminenickel (II)-tetrachloronickelate (II)
- tetrachloronickel (II)-tetraaminenickelate (0)
Correct answer: tetraamminenickel (II)-tetrachloronickelate (II)
Solution
In [Ni(NH3)4], NH3 is neutral, so Ni is +2 and the cation is tetraamminenickel(II). In [NiCl4], each Cl is -1, so Ni is +2 and because the complex is an anion, the metal name becomes nickelate: tetrachloronickelate(II).
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