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What is the IUPAC name of \( K_{2}\left[P t C l_{6}\right] ? \)
- Potassium hexachloro platinum
- Potassium hexachloro platinum (IV)
- Potassium hexa chloro platinate (IV)
- Dipotassium hexa chloro platinum
Correct answer: Potassium hexa chloro platinate (IV)
Solution
In K2[PtCl6], the complex ion is [PtCl6]2-, so platinum is in the +4 oxidation state because six chloride ligands contribute -6 total and the ion has a -2 charge. An anionic metal complex uses the metal name ending in “-ate,” giving “platinate(IV).”
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