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How many distinct isomers can be formed by the coordination compound [Cu(NH3)4][PtCl4]?

1. [Cu(NH3)3Cl] and [Pt(NH3)Cl3]
2. [Pt(NH3)3Cl] and [Cu(NH3)Cl3]
3. [Cu(NH3)3Cl] with [Pt(NH3)Cl3]
4. [Pt(NH3)3Cl] combined with [Cu(NH3)Cl3]

Correct answer: [Cu(NH3)3Cl] and [Pt(NH3)Cl3]

Solution

The given question is about the isomerism of coordination compounds. The complex [Cu(NH3)4][PtCl4] can exhibit geometrical isomerism due to the arrangement of ligands around the central metal ions. The total number of isomers is indeed four, and option A correctly represents one of the possible isomers.

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