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The complex ion [Cr(SCN)2(NH3)4]+ exhibits both linkage and geometrical isomerism. What is the correct statement regarding this?

1. The complex [Cr(SCN)2(NH3)4]+ displays both linkage and geometrical isomerism.
2. This results in the formation of the maximum number of isomers.
3. The complex [Cr(SCN)2(NH3)4]+ exhibits both types of isomerism.
4. As a result, the maximum number of isomers can be formed.

Correct answer: The complex [Cr(SCN)2(NH3)4]+ displays both linkage and geometrical isomerism.

Solution

The complex [Cr(SCN)2(NH3)4]+ can exhibit both linkage isomerism due to the ambidentate nature of SCN⁻ and geometrical isomerism due to the arrangement of ligands around the central metal ion. This makes option A correct.

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