Exams › NEET › Chemistry

The IUPAC name for sodium nitroprusside Na2[Fe(CN)5NO] is sodium pentacyanonitrosyl ferrate (III) because the NO ligand is neutral. Which calculation supports this naming?

1. 2×charge of Na + oxidation state of Fe + 5×charge of CN + 1×charge of NO = 0
2. 2×(+1) + oxidation state of Fe + 5×(−1) + 1×0 = 0
3. Oxidation state of Fe = 5 − 2 = +3, thus ferrate (III)
4. Oxidation state of Fe = 5 − 2 = +3, thus ferrate (III)

Correct answer: 2×(+1) + oxidation state of Fe + 5×(−1) + 1×0 = 0

Solution

The correct IUPAC name is determined by calculating the oxidation state of Fe. Sodium contributes +1 each, CN is −1, and NO is neutral (0). Solving gives Fe as +3, confirming ferrate (III).

Related NEET Chemistry questions

• What is the IUPAC name of \( K_{2}\left[P t C l_{6}\right] ? \)
• The structures of \( \left[N i(C O)_{4}\right] \) and \( \left[N i\left(\left(P h_{3}\right)_{3} P\right)_{2} C l_{2}\right] \) are:
• The IUPAC name of \( \left[\mathrm{Ni}\left(\mathrm{NH}_{3}\right)_{4}\right]\left[\mathrm{NiCl}_{4}\right] \) is :
• Some salts, although containing two different metallic elements, give test for one of them in solution. Such salts are:
• Actinides have higher tendency to form complexes than Lanthanides, due to
• Select the correct order of ions with respect to their ionic radii.

⚔️ Practice NEET Chemistry free + battle 1v1 →