Exams › NEET › Chemistry

Which of the following complexes has CFSE = 0?

1. Due to d5 configuration CFSE is zero.
2. cis-platin
3. [Cu(NH3)4]2+ hybridisation dsp2
4. Cu2+ = 3d9 has one unpaired e−

Correct answer: Due to d5 configuration CFSE is zero.

Solution

A d5 configuration in a high-spin complex leads to equal distribution of electrons in t2g and eg orbitals, resulting in zero crystal field stabilization energy (CFSE).

Related NEET Chemistry questions

• What is the IUPAC name of \( K_{2}\left[P t C l_{6}\right] ? \)
• The structures of \( \left[N i(C O)_{4}\right] \) and \( \left[N i\left(\left(P h_{3}\right)_{3} P\right)_{2} C l_{2}\right] \) are:
• The IUPAC name of \( \left[\mathrm{Ni}\left(\mathrm{NH}_{3}\right)_{4}\right]\left[\mathrm{NiCl}_{4}\right] \) is :
• Some salts, although containing two different metallic elements, give test for one of them in solution. Such salts are:
• Actinides have higher tendency to form complexes than Lanthanides, due to
• Select the correct order of ions with respect to their ionic radii.

⚔️ Practice NEET Chemistry free + battle 1v1 →