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In [Co(CN)6]3−, O.N. of Co is +3. CN− is a strong field ligand. Pairing of electrons occurs so in this complex no unpaired electron is present and it is low spin complex.

1. Co3+ = 3d6 4s0
2. Co3+ = 3d5 4s1
3. Co3+ = 3d4 4s2
4. Co3+ = 3d6 4s0

Correct answer: Co3+ = 3d6 4s0

Solution

In [Co(CN)6]3−, Co has an oxidation state of +3, making its electronic configuration 3d6. CN−, being a strong field ligand, causes pairing of electrons, resulting in no unpaired electrons. Thus, the configuration is 3d6 4s0.

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