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[Pt(NH3)2Cl2] is a disubstituted complex and shows only cis- and trans-isomers.

1. [Pt(NH3)2Cl2] shows cis-isomers.
2. [Pt(NH3)2Cl2] shows trans-isomers.
3. [Pt(NH3)2Cl2] shows both cis- and trans-isomers.
4. [Pt(NH3)2Cl2] does not show cis- and trans-isomers.

Correct answer: [Pt(NH3)2Cl2] shows both cis- and trans-isomers.

Solution

The complex [Pt(NH3)2Cl2] is square planar, and in such geometry, it can exhibit both cis- and trans-isomers depending on the relative positions of the ligands.

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