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As it forms two moles of silver chloride thus it has two moles of ionisable Cl.

1. [Co(NH3)5NO2]Cl2 → [Co(NH3)5NO2]2+ + 2Cl−
2. 2Cl− + 2AgNO3 → 2AgCl + 2NO3−
3. [Co(NH3)5NO2]Cl2 → [Co(NH3)5NO2]2+ + 2Cl− + 2AgNO3
4. 2Cl− + 2AgNO3 → 2AgCl + NO3−

Correct answer: [Co(NH3)5NO2]Cl2 → [Co(NH3)5NO2]2+ + 2Cl−

Solution

The compound [Co(NH3)5NO2]Cl2 ionizes to give two moles of Cl− ions, which react with AgNO3 to form two moles of AgCl. This matches the reaction in option A.

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