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The number of unpaired electrons in the complex [Cr(NH3)6]Br3 is (Atomic number Cr = 24)

1. 2
2. 0
3. 3
4. 4

Correct answer: 2

Solution

In [Cr(NH3)6]Br3, Cr is in the +3 oxidation state (as Br is -1 and there are three Br- ions). The electronic configuration of Cr3+ is [Ar] 3d3. Since NH3 is a weak field ligand, it does not cause pairing of electrons in the 3d orbitals. Thus, there are 3 unpaired electrons in the 3d orbitals.

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