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Considering H2O as a weak field ligand, the number of unpaired electrons in [Mn(H2O)6]2+ will be (At. no. of Mn = 25)

1. three
2. five
3. two
4. four

Correct answer: five

Solution

Manganese (Mn) has an atomic number of 25, so its electronic configuration is [Ar] 3d5 4s2. In the +2 oxidation state, it loses two electrons from the 4s orbital, leaving a 3d5 configuration. H2O is a weak field ligand, so it does not cause pairing of electrons in the d-orbitals. Thus, all five d-electrons remain unpaired.

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