StreakPeaked· Practice

ExamsNEETChemistry

Crystal field stabilization energy for high spin d⁴ octahedral complex is:

  1. -1.8 Δ₀
  2. -1.6 Δ₀ + P
  3. -1.2 Δ₀
  4. -0.6 Δ₀

Correct answer: -1.6 Δ₀ + P

Solution

In a high-spin d⁴ octahedral complex, three electrons occupy t₂g orbitals and one electron occupies an eg orbital. The crystal field stabilization energy (CFSE) is calculated as (-0.4 × 3) + (+0.6 × 1) = -1.2 Δ₀ + pairing energy (P), which matches option B.

Related NEET Chemistry questions

⚔️ Practice NEET Chemistry free + battle 1v1 →