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Which of these statements about [Co(CN)6]^3– is true?

1. [Co(CN)6]^3– has four unpaired electrons and will be in a low-spin configuration.
2. [Co(CN)6]^3– has four unpaired electrons and will be in a high-spin configuration.
3. [Co(CN)6]^3– has no unpaired electrons and will be in a high-spin configuration.
4. [Co(CN)6]^3– has no unpaired electrons and will be in a low-spin configuration.

Correct answer: [Co(CN)6]^3– has no unpaired electrons and will be in a low-spin configuration.

Solution

In [Co(CN)6]^3–, Co is in the +3 oxidation state (d6 configuration). CN– is a strong field ligand, causing pairing of all electrons in the t2g orbitals, resulting in no unpaired electrons and a low-spin configuration.

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