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HgCl2 and I2 both when dissolved in water containing I– ions, the pair of species formed is:

1. HgI2, I–
2. HgI4^2–, I3–
3. HgI2, I3–
4. HgI4^2–, I–

Correct answer: HgI4^2–, I3–

Solution

HgCl2 reacts with I– to form the complex ion HgI4^2–, and I2 reacts with I– to form the triiodide ion I3–. This is due to the formation of stable complexes in both cases.

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