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The geometry and magnetic behaviour of the complex [Ni(CO)4] are

1. Square planar geometry and diamagnetic
2. Tetrahedral geometry and diamagnetic
3. Tetrahedral geometry and paramagnetic
4. Square planar geometry and paramagnetic

Correct answer: Tetrahedral geometry and diamagnetic

Solution

In [Ni(CO)4], Ni is in the +0 oxidation state, and CO is a strong field ligand that causes pairing of electrons in the 3d orbital. This results in a tetrahedral geometry and diamagnetic behavior due to the absence of unpaired electrons.

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