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The calculated spin only magnetic moment of Cr2+ ion is

1. 4.90 BM
2. 5.92 BM
3. 2.84 BM
4. 3.87 BM

Correct answer: 4.90 BM

Solution

Cr2+ has an electronic configuration of [Ar] 3d4. The number of unpaired electrons is 4. Using the formula μ = √n(n+2), where n is the number of unpaired electrons, μ = √4(4+2) = √24 ≈ 4.90 BM.

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