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Magnetic moment 2.83 B.M is given by which of the following ions? (At. nos. Ti = 22, Cr = 24, Mn = 25, Ni = 28)

1. Ti³⁺
2. Ni²⁺
3. Cr³⁺
4. Mn²⁺

Correct answer: Cr³⁺

Solution

The magnetic moment is calculated using the formula μ = √n(n+2), where n is the number of unpaired electrons. For Cr³⁺, the electronic configuration is [Ar] 3d³, with 3 unpaired electrons. Substituting n = 3 gives μ = √3(3+2) = √15 ≈ 2.83 B.M.

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