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Copper sulphate dissolves in excess of KCN to give:
- [Cu(CN)4]^3−
- [Cu(CN)4]^2−
- Cu(CN)2
- CuCN
Correct answer: [Cu(CN)4]^2−
Solution
Copper sulphate reacts with excess KCN to form the complex [Cu(CN)4]^2− due to the strong complexing ability of cyanide ions with Cu(II).
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