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Magnetic moment 2.84 B.M. is given by: (At. nos, Ni = 28, Ti = 22, Cr = 24, Co = 27)

1. Ti³⁺
2. Cr²⁺
3. Co²⁺
4. Ni²⁺

Correct answer: Cr²⁺

Solution

The magnetic moment is calculated using the formula μ = √n(n+2), where n is the number of unpaired electrons. Cr²⁺ has an electronic configuration of [Ar] 3d⁴, with 4 unpaired electrons, giving μ = √4(4+2) = 2.84 B.M.

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