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Scandium ion doesn’t contain any unpaired electron in d orbitals hence it forms colourless compound.

1. Sc³⁺ -> [Ar]3d⁰; V³⁺ -> [Ar]3d²
2. Ti³⁺ -> [Ar]3d¹; Cr³⁺ -> [Ar]3d³
3. Eu -> +2, +3; La -> +3
4. Gd -> +3; Am -> +2, +3, +4, +5, +6

Correct answer: Sc³⁺ -> [Ar]3d⁰; V³⁺ -> [Ar]3d²

Solution

Sc³⁺ has the electronic configuration [Ar]3d⁰, meaning it has no unpaired electrons in its d orbitals, making its compounds colorless. The other options do not directly relate to the given property of Sc³⁺.

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