Exams › NEET › Chemistry

The electronic configuration of different species given in the option (d) are:

1. Ti³⁺: 1s²2s²2p⁶3s²3p⁶3d²
2. V³⁺: 1s²2s²2p⁶3s²3p⁶3d³
3. Cr⁴⁺: 1s²2s²2p⁶3s²3p⁶3d²
4. Mn⁵⁺: 1s²2s²2p⁶3s²3p⁶3d²

Correct answer: Cr⁴⁺: 1s²2s²2p⁶3s²3p⁶3d²

Solution

The electronic configuration of Cr⁴⁺ is correctly given as 1s²2s²2p⁶3s²3p⁶3d². Chromium has an atomic number of 24, and after losing 4 electrons, it retains 2 electrons in the 3d orbital.

Related NEET Chemistry questions

• Protons and neutrons are also called
• From the \( \alpha \) -particle scattering experiment, Rutherford concluded that: This question has multiple correct options
• Which of following was not explained by Rutherford?
• The energy of an electron in the ground state of \( \boldsymbol{H} \) atom is \( -\mathbf{1 3 . 6 e V} \) The negative sign indicates that:
• Outer electronic configuration of Cl⁻ is:
• The sub-shell with lowest value of (n + l) is filled up first. When two or more sub-shells have the same (n + l) value, the sub-shell with lowest value of 'n' is filled up first. Therefore, the correct order is:

⚔️ Practice NEET Chemistry free + battle 1v1 →