Exams › NEET › Chemistry

The no. of various oxidation states possible are +2, +3, +4, (+5), +6, +7.

1. Mn - 3d5 4s2 = 1 1 1 1 1 1
2. In Ti2+ – Ti is in +4 O.S.; 3d0 = colourless
3. In CoF63− – Co is in +3 O.S.; 3d6 = coloured
4. In CuCl2 – Cu is in +2 O.S.; 3d9 = colourless

Correct answer: In CoF63− – Co is in +3 O.S.; 3d6 = coloured

Solution

Option C is correct because Co in CoF6^3− has a +3 oxidation state, resulting in a 3d6 configuration, which is colored due to d-d transitions. Other options either have incorrect oxidation states or electronic configurations.

Related NEET Chemistry questions

• Identify the incorrect statement.
• Which one of the following ions exhibits d-d transition and paramagnetism as well?
• Magnetic moment 2.84 B.M. is given by: (At. nos, Ni = 28, Ti = 22, Cr = 24, Co = 27)
• Magnetic moment 2.83 B.M is given by which of the following ions? (At. nos. Ti = 22, Cr = 24, Mn = 25, Ni = 28)
• KMnO4 can be prepared from K2MnO4 as per the reaction: 3MnO4^2− + 2H2O → 2MnO4^− + MnO2 + 4OH^−. The reaction can go to completion by removing OH^− ions by adding:
• Which of the statements is not true?

⚔️ Practice NEET Chemistry free + battle 1v1 →