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Which one of the following statements is correct when SO2 is passed through acidified K2Cr2O7 solution?
- The solution turns blue
- The solution is decolourised
- SO2 is reduced
- Green Cr2(SO4)3 is formed
Correct answer: Green Cr2(SO4)3 is formed
Solution
When SO2 is passed through acidified K2Cr2O7 solution, it acts as a reducing agent and reduces Cr2O7^2- to Cr^3+, forming green Cr2(SO4)3.
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