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Among the following series of transition metal ions, the one where all metal ions have 3d2 electronic configuration is (At. nos. Ti = 22, V = 23, Cr = 24, Mn = 25):

1. Ti3+, V2+, Cr3+, Mn4+
2. Ti+, V4+, Cr6+, Mn7+
3. Ti4+, V3+, Cr2+, Mn3+
4. Ti2+, V3+, Cr4+, Mn5+

Correct answer: Ti3+, V2+, Cr3+, Mn4+

Solution

To determine the electronic configuration, subtract the charge from the atomic number to find the number of electrons. For Ti3+ (22-3=19), V2+ (23-2=21), Cr3+ (24-3=21), and Mn4+ (25-4=21), all have 3d2 configuration. Thus, option A is correct.

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