Cane sugar is oxidised to oxalic acid.

C₁₂H₂₂O₁₁ + 18[O] → 6(COOH)₂ + 5H₂O
C₁₂H₂₂O₁₁ + 36HNO₃ → 6(COOH)₂ + 36NO₂ + 23H₂O
C₁₂H₂₂O₁₁ + H₂O + 2NO₂ + O → 6(COOH)₂
C₁₂H₂₂O₁₁ + NaOH → Na₂C₂O₄ + H₂O

Correct answer: C₁₂H₂₂O₁₁ + 36HNO₃ → 6(COOH)₂ + 36NO₂ + 23H₂O

Solution

The reaction in option B correctly represents the oxidation of cane sugar (C₁₂H₂₂O₁₁) to oxalic acid (COOH)₂ using nitric acid (HNO₃), producing nitrogen dioxide (NO₂) and water as by-products.

Related NEET Chemistry questions

True statements for the chemical reaction of the formation of lithium oxide is: \( 4 L i(s)+O_{2}(g) \rightarrow 2 L i_{2} O(s) \)
¡) \( \boldsymbol{H}_{2} \boldsymbol{O}_{2} \rightarrow \boldsymbol{H}_{2} \boldsymbol{O}+(\boldsymbol{o}) \) ii) \( \boldsymbol{H}_{2} \boldsymbol{O}_{2}+\boldsymbol{2} \boldsymbol{I}^{-} \rightarrow \boldsymbol{I}_{2}+\boldsymbol{2} \boldsymbol{O} \boldsymbol{H}^{-}, \boldsymbol{H}_{2} \boldsymbol{O}_{2} \) acts as:
Out of the following redox reactions \( \boldsymbol{I} \cdot \boldsymbol{N} \boldsymbol{H}_{4} \boldsymbol{N} \boldsymbol{O}_{3} \stackrel{\Delta}{\rightarrow} \boldsymbol{N}_{2} \boldsymbol{O}+\boldsymbol{2} \boldsymbol{H}_{2} \boldsymbol{O} \) III.N \( \boldsymbol{H}_{4} \boldsymbol{N} \boldsymbol{O}_{2} \stackrel{\Delta}{\rightarrow} \boldsymbol{N}_{2}+\mathbf{2} \boldsymbol{H}_{2} \boldsymbol{O} \) IIII.PCl\( _{5} \stackrel{\Delta}{\rightarrow} P C l_{3}+C l_{2} \) disproportionation is not shown in:
In the following redox reaction: \( \boldsymbol{Z} \boldsymbol{n}(\boldsymbol{s})+\boldsymbol{N} \boldsymbol{O}_{\boldsymbol{3}}^{-}(\boldsymbol{a} \boldsymbol{q})+\boldsymbol{H}^{+}(\boldsymbol{a} \boldsymbol{q}) \longrightarrow \) \( Z n^{2+}(a q)+N H_{4}^{+}(a q) \) \( Z n(s) \) and \( N O_{3}^{-}(a q) \) respectively are respectively:
One mole of \( H N O_{3} \) absorbs 5 moles of electrons in a redox reaction. The reduced product of this reaction is :
Given below is a redox reaction. Which of the following types the reaction belong to? \( \boldsymbol{C u}^{+\mathbf{2 + 6 - 2}} \boldsymbol{O}_{4(a q)}+\boldsymbol{Z} \boldsymbol{n}_{(s)} \rightarrow \boldsymbol{C u}_{(s)}+ \) \( \underset{Z n S O_{4(a q)}}{+2+6+-2} \)

⚔️ Practice NEET Chemistry free + battle 1v1 →