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Given Fe3+/Fe2+ = +0.77 V and I2/2I− = 0.536V. Reduction potential of Fe3+/Fe2+ > I2/I−, so Fe3+ will be reduced and I− will be oxidised.
- Fe3+ is reduced and I− is oxidised.
- Fe3+ is oxidised and I− is reduced.
- Both Fe3+ and I− are reduced.
- Both Fe3+ and I− are oxidised.
Correct answer: Fe3+ is reduced and I− is oxidised.
Solution
The reduction potential of Fe3+/Fe2+ is higher than that of I2/2I−, meaning Fe3+ is more likely to be reduced, and I− will be oxidized to I2.
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