Exams › NEET › Chemistry
On the basis of the following E° values, the strongest oxidizing agent is:
[Fe(CN)6]3– → [Fe(CN)6]4– + e–; E° = –0.35 V
Fe2+ → Fe3+ + e–; E° = –0.77 V
- [Fe(CN)6]4–
- Fe2+
- Fe3+
- [Fe(CN)6]3–
Correct answer: [Fe(CN)6]3–
Solution
The strongest oxidizing agent is the species with the highest (most positive) reduction potential. Here, [Fe(CN)6]3– has a reduction potential of -0.35 V, which is higher than Fe2+ (-0.77 V). Thus, [Fe(CN)6]3– is the strongest oxidizing agent.
Related NEET Chemistry questions
⚔️ Practice NEET Chemistry free + battle 1v1 →