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When 0.1 mol MnO4²⁻ is oxidised, the quantity of electricity required to completely oxidise MnO4²⁻ to MnO4⁻ is:

1. 96500 C
2. 2 × 96500 C
3. 9650 C
4. 96.5 C

Correct answer: 96500 C

Solution

The oxidation of MnO4²⁻ to MnO4⁻ involves a one-electron transfer per ion. For 0.1 mol of MnO4²⁻, the total charge required is 0.1 × 96500 C = 9650 C.

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