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Maximum change in oxidation number is observed in Cl (+5 to -1).

1. KClO3 + H2C2O4 + H2SO4 → K2SO4
2. KCl + H2C2O4 + H2O
3. KClO3 + H2C2O4 + H2SO4 → K2SO4 + Cl2 + H2O
4. KClO3 + H2C2O4 → K2C2O4 + Cl2

Correct answer: KClO3 + H2C2O4 + H2SO4 → K2SO4 + Cl2 + H2O

Solution

In option C, Cl in KClO3 changes from +5 to 0 in Cl2, and further to -1 in KCl, showing the maximum change in oxidation number. The reaction is balanced and consistent with the given conditions.

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