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When Cl2 gas reacts with hot and concentrated sodium hydroxide solution, the oxidation number of chlorine changes from:

1. zero to -1 and zero to -5
2. zero to -1 and zero to +5
3. zero to -1 and zero to +3
4. zero to -1 and zero to -3

Correct answer: zero to -1 and zero to +5

Solution

When Cl2 reacts with hot and concentrated NaOH, it undergoes disproportionation. One chlorine atom is reduced to Cl⁻ (oxidation number 0 to -1), and the other is oxidized to ClO3⁻ (oxidation number 0 to +5).

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