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The hybridization involved in complex [Ni(CN)4]2− is (At. No. Ni = 28)

1. dsp2
2. sp3
3. d2sp2
4. d2sp3

Correct answer: dsp2

Solution

In [Ni(CN)4]2−, Ni is in the +2 oxidation state, leaving it with a 3d8 configuration. CN− is a strong field ligand, causing pairing of electrons in the 3d orbitals. This results in dsp2 hybridization, forming a square planar geometry.

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