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The orbital angular momentum of a p-electron is given as:

1. h / √2π
2. √3 h / 2π
3. √3 h / 2 π
4. √6 h / 2π

Correct answer: √3 h / 2π

Solution

The orbital angular momentum of an electron is given by the formula √l(l+1)h/2π, where l is the azimuthal quantum number. For a p-electron, l = 1, so the angular momentum becomes √1(1+1)h/2π = √2h/2π.

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