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The correct set of four quantum numbers for the valence electron of rubidium atom (Z = 37) is

1. 5, 1, 1 + 1/2
2. 6, 0, 0 + 1/2
3. 5, 0, 0 + 1/2
4. 5, 1, 0 + 1/2

Correct answer: 5, 0, 0 + 1/2

Solution

Rubidium (Z = 37) has its valence electron in the 5s orbital. The quantum numbers for this electron are: n = 5 (principal quantum number), l = 0 (s orbital), m = 0 (magnetic quantum number), and spin = +1/2.

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