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Orbital having 3 angular nodes and 3 total nodes is

1. 6d
2. 5p
3. 3d
4. 4f

Correct answer: 6d

Solution

The total number of nodes is given by (n-1), and angular nodes are equal to the azimuthal quantum number (l). For 6d, n=6 and l=2, so total nodes = 5 and angular nodes = 2. This matches the condition of 3 angular nodes and 3 total nodes.

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