Exams › NEET › Chemistry

Given: The mass of electron is 9.11 × 10⁻³¹ kg, Planck constant is 6.626 × 10⁻³⁴ Js, the uncertainty involved in the measurement of velocity within a distance of 0.1 Å is

1. 5.79 × 10⁷ ms⁻¹
2. 5.79 × 10⁸ ms⁻¹
3. 5.79 × 10⁵ ms⁻¹
4. 5.79 × 10⁶ ms⁻¹

Correct answer: 5.79 × 10⁷ ms⁻¹

Solution

Using Heisenberg's uncertainty principle, Δx × mΔv ≥ h/4π. Substituting Δx = 0.1 Å = 0.1 × 10⁻¹⁰ m, m = 9.11 × 10⁻³¹ kg, and h = 6.626 × 10⁻³⁴ Js, we calculate Δv ≈ 5.79 × 10⁷ ms⁻¹.

Related NEET Chemistry questions

• Protons and neutrons are also called
• From the \( \alpha \) -particle scattering experiment, Rutherford concluded that: This question has multiple correct options
• Which of following was not explained by Rutherford?
• The energy of an electron in the ground state of \( \boldsymbol{H} \) atom is \( -\mathbf{1 3 . 6 e V} \) The negative sign indicates that:
• Outer electronic configuration of Cl⁻ is:
• The sub-shell with lowest value of (n + l) is filled up first. When two or more sub-shells have the same (n + l) value, the sub-shell with lowest value of 'n' is filled up first. Therefore, the correct order is:

⚔️ Practice NEET Chemistry free + battle 1v1 →