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The energies E₁ and E₂ of two radiations are 25 eV and 50 eV, respectively. The relation between their wavelengths i.e., λ₁ and λ₂ will be:
- λ₁ = λ₂
- λ₁ = 2λ₂
- λ₁ = 4λ₂
- λ₁ = 1/2 λ₂
Correct answer: λ₁ = 2λ₂
Solution
Energy (E) and wavelength (λ) are inversely proportional (E = hc/λ). Since E₂ is double E₁, λ₁ will be twice λ₂, i.e., λ₁ = 2λ₂.
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