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Number of neutrons in a parent nucleus X, which gives ¹⁴₇N nucleus, after two successive β emissions, would be:

1. 9
2. 6
3. 7
4. 8

Correct answer: 9

Solution

The parent nucleus undergoes two successive β emissions to form ¹⁴₇N. Each β emission increases the atomic number by 1, so the parent nucleus must have been ¹⁴₅B. The number of neutrons in ¹⁴₅B is 14 (mass number) - 5 (atomic number) = 9.

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