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The magnetic moment μ = √(n(n+2)) is given. On solving for n = 3, Cr3+ will have configuration as 1s2 2s2 2p6 3s2 3p6 3d3. What is the number of unpaired electrons?

1. 3 unpaired electrons
2. 4 unpaired electrons
3. 5 unpaired electrons
4. 6 unpaired electrons

Correct answer: 3 unpaired electrons

Solution

Cr3+ has a configuration of 3d3, meaning there are 3 electrons in the d-orbital. These electrons occupy separate orbitals due to Hund's rule, resulting in 3 unpaired electrons.

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