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Among [Ni(CO)4], [Ni(CN)4]2-, [NiCl4]2-, the hybridization states of the Ni atom are, respectively (At. No. of Ni = 28)

1. sp3, dsp2, dsp2
2. sp3, dsp2, sp3
3. sp3, sp3, dsp2
4. dsp2, sp3, sp3

Correct answer: sp3, dsp2, sp3

Solution

In [Ni(CO)4], Ni is in a zero oxidation state, and CO is a strong field ligand, leading to sp3 hybridization. In [Ni(CN)4]2-, CN- is a strong field ligand, causing dsp2 hybridization. In [NiCl4]2-, Cl- is a weak field ligand, resulting in sp3 hybridization.

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