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Oxidation number of Ni in [Ni(C2O4)3]4− is

1. 3
2. 4
3. 2
4. 6

Correct answer: 2

Solution

The oxalate ion (C2O4) has a charge of -2. Since there are three oxalate ions, their total charge is -6. The overall charge of the complex is -4, so the oxidation number of Ni must be +2 to balance the charges.

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