Exams › NEET › Chemistry

The total number of possible isomers for the complex compound [Cu(NH3)4][PtCl4] is

1. 3
2. 6
3. 5
4. 4

Correct answer: 3

Solution

The complex [Cu(NH3)4][PtCl4] can exhibit geometrical isomerism due to the square planar arrangement of ligands around Pt and Cu. Considering all possible arrangements, the total number of isomers is 3.

Related NEET Chemistry questions

• What is the IUPAC name of \( K_{2}\left[P t C l_{6}\right] ? \)
• The structures of \( \left[N i(C O)_{4}\right] \) and \( \left[N i\left(\left(P h_{3}\right)_{3} P\right)_{2} C l_{2}\right] \) are:
• The IUPAC name of \( \left[\mathrm{Ni}\left(\mathrm{NH}_{3}\right)_{4}\right]\left[\mathrm{NiCl}_{4}\right] \) is :
• Some salts, although containing two different metallic elements, give test for one of them in solution. Such salts are:
• Actinides have higher tendency to form complexes than Lanthanides, due to
• Select the correct order of ions with respect to their ionic radii.

⚔️ Practice NEET Chemistry free + battle 1v1 →